Base | Representation |
---|---|
bin | 11000100110111001… |
… | …00100001101100011 |
3 | 1021002201010022212222 |
4 | 30103130210031203 |
5 | 204024024013342 |
6 | 10022532541255 |
7 | 645245661503 |
oct | 142334441543 |
9 | 37081108788 |
10 | 13211157347 |
11 | 566a399063 |
12 | 268848182b |
13 | 132706458b |
14 | 8d4813a03 |
15 | 524c61ed2 |
hex | 313724363 |
13211157347 has 4 divisors (see below), whose sum is σ = 13315182336. Its totient is φ = 13107132360.
The previous prime is 13211157341. The next prime is 13211157353. The reversal of 13211157347 is 74375111231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74375111231 = 17 ⋅4375006543.
It is an interprime number because it is at equal distance from previous prime (13211157341) and next prime (13211157353).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13211157347 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13211157341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52012304 + ... + 52012557.
It is an arithmetic number, because the mean of its divisors is an integer number (3328795584).
Almost surely, 213211157347 is an apocalyptic number.
13211157347 is a deficient number, since it is larger than the sum of its proper divisors (104024989).
13211157347 is a wasteful number, since it uses less digits than its factorization.
13211157347 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104024988.
The product of its digits is 17640, while the sum is 35.
Adding to 13211157347 its reverse (74375111231), we get a palindrome (87586268578).
The spelling of 13211157347 in words is "thirteen billion, two hundred eleven million, one hundred fifty-seven thousand, three hundred forty-seven".
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