Base | Representation |
---|---|
bin | 11110000010011110111010… |
… | …001101011100001110000111 |
3 | 122022202210020001011102222102 |
4 | 132002132322031130032013 |
5 | 114304010410411041203 |
6 | 1144551231531422315 |
7 | 36553531043212130 |
oct | 3602367215341607 |
9 | 568683201142872 |
10 | 132112023143303 |
11 | 39105437a02685 |
12 | 129982412b499b |
13 | 5894158504868 |
14 | 248a3827d2c87 |
15 | 104180c0a3888 |
hex | 7827ba35c387 |
132112023143303 has 24 divisors (see below), whose sum is σ = 156116034547200. Its totient is φ = 109513476068400.
The previous prime is 132112023143299. The next prime is 132112023143341. The reversal of 132112023143303 is 303341320211231.
It is not a de Polignac number, because 132112023143303 - 22 = 132112023143299 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132112023163303) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3665798 + ... + 16663196.
It is an arithmetic number, because the mean of its divisors is an integer number (6504834772800).
Almost surely, 2132112023143303 is an apocalyptic number.
132112023143303 is a deficient number, since it is larger than the sum of its proper divisors (24004011403897).
132112023143303 is a wasteful number, since it uses less digits than its factorization.
132112023143303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12998979 (or 12998948 counting only the distinct ones).
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 132112023143303 its reverse (303341320211231), we get a palindrome (435453343354534).
The spelling of 132112023143303 in words is "one hundred thirty-two trillion, one hundred twelve billion, twenty-three million, one hundred forty-three thousand, three hundred three".
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