Base | Representation |
---|---|
bin | 111101100001001111… |
… | …1100001011100100001 |
3 | 110122000010011010100021 |
4 | 1323002133201130201 |
5 | 4131031141442431 |
6 | 140405203553441 |
7 | 12354601000135 |
oct | 1730237413441 |
9 | 418003133307 |
10 | 132112062241 |
11 | 510348a6815 |
12 | 2173008b881 |
13 | c5c5626ac3 |
14 | 6573bb53c5 |
15 | 36834aeb11 |
hex | 1ec27e1721 |
132112062241 has 4 divisors (see below), whose sum is σ = 133972795584. Its totient is φ = 130251328900.
The previous prime is 132112062233. The next prime is 132112062283. The reversal of 132112062241 is 142260211231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 132112062241 - 23 = 132112062233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132112062211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 930366565 + ... + 930366706.
It is an arithmetic number, because the mean of its divisors is an integer number (33493198896).
Almost surely, 2132112062241 is an apocalyptic number.
It is an amenable number.
132112062241 is a deficient number, since it is larger than the sum of its proper divisors (1860733343).
132112062241 is an equidigital number, since it uses as much as digits as its factorization.
132112062241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1860733342.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 132112062241 its reverse (142260211231), we get a palindrome (274372273472).
The spelling of 132112062241 in words is "one hundred thirty-two billion, one hundred twelve million, sixty-two thousand, two hundred forty-one".
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