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142260211231 is a prime number
BaseRepresentation
bin1000010001111101011…
…1101000111000011111
3111121012100200111200021
42010133113220320133
54312322103224411
6145204202013011
713164224562265
oct2043727507037
9447170614607
10142260211231
11553721a9306
12236a27a7167
1310551c157a8
146c578a0435
153a79383a71
hex211f5e8e1f

142260211231 has 2 divisors, whose sum is σ = 142260211232. Its totient is φ = 142260211230.

The previous prime is 142260211213. The next prime is 142260211307. The reversal of 142260211231 is 132112062241.

Together with previous prime (142260211213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 142260211231 - 213 = 142260203039 is a prime.

It is a super-2 number, since 2×1422602112312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 142260211196 and 142260211205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142260211211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71130105615 + 71130105616.

It is an arithmetic number, because the mean of its divisors is an integer number (71130105616).

Almost surely, 2142260211231 is an apocalyptic number.

142260211231 is a deficient number, since it is larger than the sum of its proper divisors (1).

142260211231 is an equidigital number, since it uses as much as digits as its factorization.

142260211231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 142260211231 its reverse (132112062241), we get a palindrome (274372273472).

The spelling of 142260211231 in words is "one hundred forty-two billion, two hundred sixty million, two hundred eleven thousand, two hundred thirty-one".