Base | Representation |
---|---|
bin | 111101100001001111… |
… | …1101010111100001101 |
3 | 110122000010020002200201 |
4 | 1323002133222330031 |
5 | 4131031144214013 |
6 | 140405204453501 |
7 | 12354601221415 |
oct | 1730237527415 |
9 | 418003202621 |
10 | 132112101133 |
11 | 51034922a61 |
12 | 217300aa291 |
13 | c5c563b70c |
14 | 6573bc5645 |
15 | 36834bb3dd |
hex | 1ec27eaf0d |
132112101133 has 2 divisors, whose sum is σ = 132112101134. Its totient is φ = 132112101132.
The previous prime is 132112101113. The next prime is 132112101151. The reversal of 132112101133 is 331101211231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112894656004 + 19217445129 = 335998^2 + 138627^2 .
It is a cyclic number.
It is not a de Polignac number, because 132112101133 - 221 = 132110003981 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132112101133.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132112101103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66056050566 + 66056050567.
It is an arithmetic number, because the mean of its divisors is an integer number (66056050567).
Almost surely, 2132112101133 is an apocalyptic number.
It is an amenable number.
132112101133 is a deficient number, since it is larger than the sum of its proper divisors (1).
132112101133 is an equidigital number, since it uses as much as digits as its factorization.
132112101133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 132112101133 its reverse (331101211231), we get a palindrome (463213312364).
The spelling of 132112101133 in words is "one hundred thirty-two billion, one hundred twelve million, one hundred one thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •