13211215331 has 2 divisors, whose sum is σ = 13211215332. Its totient is φ = 13211215330.

The previous prime is 13211215319. The next prime is 13211215357. The reversal of 13211215331 is 13351211231.

It is a weak prime.

It is an emirp because it is prime and its reverse (13351211231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13211215331 - 2¹⁰ = 13211214307 is a prime.

It is a super-2 number, since 2×13211215331² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13211215297 and 13211215306.

It is not a weakly prime, because it can be changed into another prime (13211215531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605607665 + 6605607666.

It is an arithmetic number, because the mean of its divisors is an integer number (6605607666).

Almost surely, 2^13211215331 is an apocalyptic number.

13211215331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13211215331 is an equidigital number, since it uses as much as digits as its factorization.

13211215331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 540, while the sum is 23.

Adding to 13211215331 its reverse (13351211231), we get a palindrome (26562426562).

The spelling of 13211215331 in words is "thirteen billion, two hundred eleven million, two hundred fifteen thousand, three hundred thirty-one".