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1321123140433 = 79101165575027
BaseRepresentation
bin10011001110011001000…
…100110101001101010001
311200022001100021011111201
4103032121010311031101
5133121130010443213
62450525433511201
7164306443260235
oct23163104651521
94608040234451
101321123140433
1146a315631248
12194061572501
13977733956c5
1447d2aab45c5
15245735986dd
hex13399135351

1321123140433 has 8 divisors (see below), whose sum is σ = 1351092228480. Its totient is φ = 1291485202800.

The previous prime is 1321123140413. The next prime is 1321123140457. The reversal of 1321123140433 is 3340413211231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1321123140433 - 25 = 1321123140401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1321123140413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 82779535 + ... + 82795492.

It is an arithmetic number, because the mean of its divisors is an integer number (168886528560).

Almost surely, 21321123140433 is an apocalyptic number.

It is an amenable number.

1321123140433 is a deficient number, since it is larger than the sum of its proper divisors (29969088047).

1321123140433 is a wasteful number, since it uses less digits than its factorization.

1321123140433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 165575207.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1321123140433 its reverse (3340413211231), we get a palindrome (4661536351664).

The spelling of 1321123140433 in words is "one trillion, three hundred twenty-one billion, one hundred twenty-three million, one hundred forty thousand, four hundred thirty-three".

Divisors: 1 79 101 7979 165575027 13080427133 16723077727 1321123140433