Base | Representation |
---|---|
bin | 1100000000111111111011… |
… | …1110011111110100001111 |
3 | 1201202222200100221001102120 |
4 | 3000033332332133310033 |
5 | 3212423221332400221 |
6 | 44033104412424023 |
7 | 2532325246053162 |
oct | 300177676376417 |
9 | 51688610831376 |
10 | 13211302231311 |
11 | 4233977767628 |
12 | 1594532478013 |
13 | 74aa88701512 |
14 | 3396051abad9 |
15 | 17d9c9e9a5c6 |
hex | c03fef9fd0f |
13211302231311 has 4 divisors (see below), whose sum is σ = 17615069641752. Its totient is φ = 8807534820872.
The previous prime is 13211302231261. The next prime is 13211302231333. The reversal of 13211302231311 is 11313220311231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13211302231311 - 214 = 13211302214927 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13211302231381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2201883705216 + ... + 2201883705221.
It is an arithmetic number, because the mean of its divisors is an integer number (4403767410438).
Almost surely, 213211302231311 is an apocalyptic number.
13211302231311 is a deficient number, since it is larger than the sum of its proper divisors (4403767410441).
13211302231311 is an equidigital number, since it uses as much as digits as its factorization.
13211302231311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4403767410440.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 13211302231311 its reverse (11313220311231), we get a palindrome (24524522542542).
The spelling of 13211302231311 in words is "thirteen trillion, two hundred eleven billion, three hundred two million, two hundred thirty-one thousand, three hundred eleven".
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