Base | Representation |
---|---|
bin | 11110000010011111111100… |
… | …111011001011111110000111 |
3 | 122022202220010001022011220101 |
4 | 132002133330323023332013 |
5 | 114304020203430302443 |
6 | 1144551534553544531 |
7 | 36553600554051313 |
oct | 3602377473137607 |
9 | 568686101264811 |
10 | 132113142431623 |
11 | 391059617a1551 |
12 | 129984b4115147 |
13 | 58942a6379a42 |
14 | 248a44b312b43 |
15 | 104187549984d |
hex | 7827fcecbf87 |
132113142431623 has 4 divisors (see below), whose sum is σ = 132114310168680. Its totient is φ = 132111974694568.
The previous prime is 132113142431573. The next prime is 132113142431657. The reversal of 132113142431623 is 326134241311231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132113142431623 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132113142401623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 583698808 + ... + 583925101.
It is an arithmetic number, because the mean of its divisors is an integer number (33028577542170).
Almost surely, 2132113142431623 is an apocalyptic number.
132113142431623 is a deficient number, since it is larger than the sum of its proper divisors (1167737057).
132113142431623 is a wasteful number, since it uses less digits than its factorization.
132113142431623 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1167737056.
The product of its digits is 62208, while the sum is 37.
Adding to 132113142431623 its reverse (326134241311231), we get a palindrome (458247383742854).
The spelling of 132113142431623 in words is "one hundred thirty-two trillion, one hundred thirteen billion, one hundred forty-two million, four hundred thirty-one thousand, six hundred twenty-three".
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