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132114442139749 is a prime number
BaseRepresentation
bin11110000010100001001010…
…011001001011100001100101
3122022210000110121221012021101
4132002201022121023201211
5114304030334141432444
61144552311543120101
736553645015304656
oct3602411231134145
9568700417835241
10132114442139749
113910646940a4a3
12129987b7443031
135894452711bc4
14248a531b9952d
1510418ee62d3d4
hex78284a64b865

132114442139749 has 2 divisors, whose sum is σ = 132114442139750. Its totient is φ = 132114442139748.

The previous prime is 132114442139737. The next prime is 132114442139791. The reversal of 132114442139749 is 947931244411231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84625556616225 + 47488885523524 = 9199215^2 + 6891218^2 .

It is a cyclic number.

It is not a de Polignac number, because 132114442139749 - 25 = 132114442139717 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132114442139749.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132114242139749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057221069874 + 66057221069875.

It is an arithmetic number, because the mean of its divisors is an integer number (66057221069875).

Almost surely, 2132114442139749 is an apocalyptic number.

It is an amenable number.

132114442139749 is a deficient number, since it is larger than the sum of its proper divisors (1).

132114442139749 is an equidigital number, since it uses as much as digits as its factorization.

132114442139749 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5225472, while the sum is 55.

The spelling of 132114442139749 in words is "one hundred thirty-two trillion, one hundred fourteen billion, four hundred forty-two million, one hundred thirty-nine thousand, seven hundred forty-nine".