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132114442140017 is a prime number
BaseRepresentation
bin11110000010100001001010…
…011001001011100101110001
3122022210000110121221012122022
4132002201022121023211301
5114304030334141440032
61144552311543121225
736553645015305521
oct3602411231134561
9568700417835568
10132114442140017
113910646940a717
12129987b7443215
13589445271206c
14248a531b99681
1510418ee62d512
hex78284a64b971

132114442140017 has 2 divisors, whose sum is σ = 132114442140018. Its totient is φ = 132114442140016.

The previous prime is 132114442139983. The next prime is 132114442140049. The reversal of 132114442140017 is 710041244411231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109896454888801 + 22217987251216 = 10483151^2 + 4713596^2 .

It is a cyclic number.

It is not a de Polignac number, because 132114442140017 - 210 = 132114442138993 is a prime.

It is not a weakly prime, because it can be changed into another prime (132114442140217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057221070008 + 66057221070009.

It is an arithmetic number, because the mean of its divisors is an integer number (66057221070009).

Almost surely, 2132114442140017 is an apocalyptic number.

It is an amenable number.

132114442140017 is a deficient number, since it is larger than the sum of its proper divisors (1).

132114442140017 is an equidigital number, since it uses as much as digits as its factorization.

132114442140017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21504, while the sum is 35.

Adding to 132114442140017 its reverse (710041244411231), we get a palindrome (842155686551248).

The spelling of 132114442140017 in words is "one hundred thirty-two trillion, one hundred fourteen billion, four hundred forty-two million, one hundred forty thousand, seventeen".