Base | Representation |
---|---|
bin | 11110000010100001001010… |
… | …011001001011100101110001 |
3 | 122022210000110121221012122022 |
4 | 132002201022121023211301 |
5 | 114304030334141440032 |
6 | 1144552311543121225 |
7 | 36553645015305521 |
oct | 3602411231134561 |
9 | 568700417835568 |
10 | 132114442140017 |
11 | 3910646940a717 |
12 | 129987b7443215 |
13 | 589445271206c |
14 | 248a531b99681 |
15 | 10418ee62d512 |
hex | 78284a64b971 |
132114442140017 has 2 divisors, whose sum is σ = 132114442140018. Its totient is φ = 132114442140016.
The previous prime is 132114442139983. The next prime is 132114442140049. The reversal of 132114442140017 is 710041244411231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 109896454888801 + 22217987251216 = 10483151^2 + 4713596^2 .
It is a cyclic number.
It is not a de Polignac number, because 132114442140017 - 210 = 132114442138993 is a prime.
It is not a weakly prime, because it can be changed into another prime (132114442140217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057221070008 + 66057221070009.
It is an arithmetic number, because the mean of its divisors is an integer number (66057221070009).
Almost surely, 2132114442140017 is an apocalyptic number.
It is an amenable number.
132114442140017 is a deficient number, since it is larger than the sum of its proper divisors (1).
132114442140017 is an equidigital number, since it uses as much as digits as its factorization.
132114442140017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 35.
Adding to 132114442140017 its reverse (710041244411231), we get a palindrome (842155686551248).
The spelling of 132114442140017 in words is "one hundred thirty-two trillion, one hundred fourteen billion, four hundred forty-two million, one hundred forty thousand, seventeen".
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