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132114442139983 is a prime number
BaseRepresentation
bin11110000010100001001010…
…011001001011100101001111
3122022210000110121221012121001
4132002201022121023211033
5114304030334141434413
61144552311543121131
736553645015305442
oct3602411231134517
9568700417835531
10132114442139983
113910646940a696
12129987b74431a7
135894452712044
14248a531b99659
1510418ee62d4dd
hex78284a64b94f

132114442139983 has 2 divisors, whose sum is σ = 132114442139984. Its totient is φ = 132114442139982.

The previous prime is 132114442139971. The next prime is 132114442140017. The reversal of 132114442139983 is 389931244411231.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (389931244411231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132114442139983 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132114442133983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057221069991 + 66057221069992.

It is an arithmetic number, because the mean of its divisors is an integer number (66057221069992).

Almost surely, 2132114442139983 is an apocalyptic number.

132114442139983 is a deficient number, since it is larger than the sum of its proper divisors (1).

132114442139983 is an equidigital number, since it uses as much as digits as its factorization.

132114442139983 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4478976, while the sum is 55.

The spelling of 132114442139983 in words is "one hundred thirty-two trillion, one hundred fourteen billion, four hundred forty-two million, one hundred thirty-nine thousand, nine hundred eighty-three".