Base | Representation |
---|---|
bin | 11110000010100001001010… |
… | …011001001011100101001111 |
3 | 122022210000110121221012121001 |
4 | 132002201022121023211033 |
5 | 114304030334141434413 |
6 | 1144552311543121131 |
7 | 36553645015305442 |
oct | 3602411231134517 |
9 | 568700417835531 |
10 | 132114442139983 |
11 | 3910646940a696 |
12 | 129987b74431a7 |
13 | 5894452712044 |
14 | 248a531b99659 |
15 | 10418ee62d4dd |
hex | 78284a64b94f |
132114442139983 has 2 divisors, whose sum is σ = 132114442139984. Its totient is φ = 132114442139982.
The previous prime is 132114442139971. The next prime is 132114442140017. The reversal of 132114442139983 is 389931244411231.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (389931244411231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132114442139983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132114442133983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057221069991 + 66057221069992.
It is an arithmetic number, because the mean of its divisors is an integer number (66057221069992).
Almost surely, 2132114442139983 is an apocalyptic number.
132114442139983 is a deficient number, since it is larger than the sum of its proper divisors (1).
132114442139983 is an equidigital number, since it uses as much as digits as its factorization.
132114442139983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4478976, while the sum is 55.
The spelling of 132114442139983 in words is "one hundred thirty-two trillion, one hundred fourteen billion, four hundred forty-two million, one hundred thirty-nine thousand, nine hundred eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •