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132115654423 = 197159670097
BaseRepresentation
bin111101100001010110…
…1001110011100010111
3110122000100220121220001
41323002231032130113
54131033101420143
6140405412552131
712354643351024
oct1730255163427
9418010817801
10132115654423
115103692a665
1221731322647
13c5c62b3b5c
14657446c54b
15368396e14d
hex1ec2b4e717

132115654423 has 4 divisors (see below), whose sum is σ = 132116521680. Its totient is φ = 132114787168.

The previous prime is 132115654421. The next prime is 132115654457. The reversal of 132115654423 is 324456511231.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 132115654423 - 21 = 132115654421 is a prime.

It is a super-2 number, since 2×1321156544232 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132115654421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137890 + ... + 532207.

It is an arithmetic number, because the mean of its divisors is an integer number (33029130420).

Almost surely, 2132115654423 is an apocalyptic number.

132115654423 is a deficient number, since it is larger than the sum of its proper divisors (867257).

132115654423 is an equidigital number, since it uses as much as digits as its factorization.

132115654423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 867256.

The product of its digits is 86400, while the sum is 37.

The spelling of 132115654423 in words is "one hundred thirty-two billion, one hundred fifteen million, six hundred fifty-four thousand, four hundred twenty-three".

Divisors: 1 197159 670097 132115654423