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132115704131 = 667319798547
BaseRepresentation
bin111101100001010110…
…1011010100101000011
3110122000101000011002002
41323002231122211003
54131033110013011
6140405414014215
712354643645655
oct1730255324503
9418011004062
10132115704131
1151036963a44
122173134736b
13c5c6300678
1465744826d5
15368397dc3b
hex1ec2b5a943

132115704131 has 4 divisors (see below), whose sum is σ = 132135509352. Its totient is φ = 132095898912.

The previous prime is 132115704121. The next prime is 132115704143. The reversal of 132115704131 is 131407511231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132115704131 - 234 = 114935834947 is a prime.

It is a super-2 number, since 2×1321157041312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132115704094 and 132115704103.

It is not an unprimeable number, because it can be changed into a prime (132115704121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9892601 + ... + 9905946.

It is an arithmetic number, because the mean of its divisors is an integer number (33033877338).

Almost surely, 2132115704131 is an apocalyptic number.

132115704131 is a deficient number, since it is larger than the sum of its proper divisors (19805221).

132115704131 is an equidigital number, since it uses as much as digits as its factorization.

132115704131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19805220.

The product of its (nonzero) digits is 2520, while the sum is 29.

The spelling of 132115704131 in words is "one hundred thirty-two billion, one hundred fifteen million, seven hundred four thousand, one hundred thirty-one".

Divisors: 1 6673 19798547 132115704131