Search a number
-
+
13212010541335 = 58534906963131
BaseRepresentation
bin1100000001000010100100…
…1100011111000100010111
31201210001111201201221010011
43000100221030133010113
53212431144144310320
644033302554141051
72532351636435034
oct300205114370427
951701451657104
1013212010541335
114234200572411
1215946ab721787
1374ab6c390188
143396712aa38b
1517da1c26005a
hexc042931f117

13212010541335 has 16 divisors (see below), whose sum is σ = 15873574217760. Its totient is φ = 10556834958720.

The previous prime is 13212010541293. The next prime is 13212010541347. The reversal of 13212010541335 is 53314501021231.

It is not a de Polignac number, because 13212010541335 - 213 = 13212010533143 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13212010541297 and 13212010541306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 209247720 + ... + 209310850.

It is an arithmetic number, because the mean of its divisors is an integer number (992098388610).

Almost surely, 213212010541335 is an apocalyptic number.

13212010541335 is a deficient number, since it is larger than the sum of its proper divisors (2661563676425).

13212010541335 is an equidigital number, since it uses as much as digits as its factorization.

13212010541335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113058.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 13212010541335 its reverse (53314501021231), we get a palindrome (66526511562566).

The spelling of 13212010541335 in words is "thirteen trillion, two hundred twelve billion, ten million, five hundred forty-one thousand, three hundred thirty-five".

Divisors: 1 5 853 4265 49069 63131 245345 315655 41855857 53850743 209279285 269253715 3097775039 15488875195 2642402108267 13212010541335