Base | Representation |
---|---|
bin | 11110000010100110100001… |
… | …110110100010100010101011 |
3 | 122022210120100012200102112021 |
4 | 132002212201312202202223 |
5 | 114304124134312440131 |
6 | 1144555103424525311 |
7 | 36554240555012422 |
oct | 3602464166424253 |
9 | 568716305612467 |
10 | 132120204421291 |
11 | 39108956035949 |
12 | 12999945180837 |
13 | 5894b60478458 |
14 | 248a91b1a82b9 |
15 | 1041b3a45ae11 |
hex | 7829a1da28ab |
132120204421291 has 2 divisors, whose sum is σ = 132120204421292. Its totient is φ = 132120204421290.
The previous prime is 132120204421187. The next prime is 132120204421327. The reversal of 132120204421291 is 192124402021231.
It is a strong prime.
It is an emirp because it is prime and its reverse (192124402021231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132120204421291 is a prime.
It is not a weakly prime, because it can be changed into another prime (132120204421591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060102210645 + 66060102210646.
It is an arithmetic number, because the mean of its divisors is an integer number (66060102210646).
Almost surely, 2132120204421291 is an apocalyptic number.
132120204421291 is a deficient number, since it is larger than the sum of its proper divisors (1).
132120204421291 is an equidigital number, since it uses as much as digits as its factorization.
132120204421291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 34.
The spelling of 132120204421291 in words is "one hundred thirty-two trillion, one hundred twenty billion, two hundred four million, four hundred twenty-one thousand, two hundred ninety-one".
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