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132120204421327 is a prime number
BaseRepresentation
bin11110000010100110100001…
…110110100010100011001111
3122022210120100012200102120121
4132002212201312202203033
5114304124134312440302
61144555103424525411
736554240555012503
oct3602464166424317
9568716305612517
10132120204421327
1139108956035981
1212999945180867
135894b60478485
14248a91b1a8303
151041b3a45ae37
hex7829a1da28cf

132120204421327 has 2 divisors, whose sum is σ = 132120204421328. Its totient is φ = 132120204421326.

The previous prime is 132120204421291. The next prime is 132120204421397. The reversal of 132120204421327 is 723124402021231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132120204421327 - 231 = 132118056937679 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132120204421292 and 132120204421301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132120204421397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060102210663 + 66060102210664.

It is an arithmetic number, because the mean of its divisors is an integer number (66060102210664).

Almost surely, 2132120204421327 is an apocalyptic number.

132120204421327 is a deficient number, since it is larger than the sum of its proper divisors (1).

132120204421327 is an equidigital number, since it uses as much as digits as its factorization.

132120204421327 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32256, while the sum is 34.

Adding to 132120204421327 its reverse (723124402021231), we get a palindrome (855244606442558).

The spelling of 132120204421327 in words is "one hundred thirty-two trillion, one hundred twenty billion, two hundred four million, four hundred twenty-one thousand, three hundred twenty-seven".