Base | Representation |
---|---|
bin | 1100000001000010100111… |
… | …0101001100000011010111 |
3 | 1201210001112110211000121221 |
4 | 3000100221311030003113 |
5 | 3212431204412230401 |
6 | 44033304014551211 |
7 | 2532352126224664 |
oct | 300205165140327 |
9 | 51701473730557 |
10 | 13212021211351 |
11 | 423420659aa06 |
12 | 15946b3208507 |
13 | 74ab716579b1 |
14 | 339672886a6b |
15 | 17da1d16b7a1 |
hex | c0429d4c0d7 |
13212021211351 has 2 divisors, whose sum is σ = 13212021211352. Its totient is φ = 13212021211350.
The previous prime is 13212021211223. The next prime is 13212021211369. The reversal of 13212021211351 is 15311212021231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13212021211351 - 27 = 13212021211223 is a prime.
It is a super-2 number, since 2×132120212113512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13212021211451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606010605675 + 6606010605676.
It is an arithmetic number, because the mean of its divisors is an integer number (6606010605676).
Almost surely, 213212021211351 is an apocalyptic number.
13212021211351 is a deficient number, since it is larger than the sum of its proper divisors (1).
13212021211351 is an equidigital number, since it uses as much as digits as its factorization.
13212021211351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 13212021211351 its reverse (15311212021231), we get a palindrome (28523233232582).
The spelling of 13212021211351 in words is "thirteen trillion, two hundred twelve billion, twenty-one million, two hundred eleven thousand, three hundred fifty-one".
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