Base | Representation |
---|---|
bin | 11110000010100110100010… |
… | …011100101110101010110111 |
3 | 122022210120100220112001020112 |
4 | 132002212202130232222313 |
5 | 114304124144343314224 |
6 | 1144555104423253235 |
7 | 36554241036056432 |
oct | 3602464234565267 |
9 | 568716326461215 |
10 | 132120214432439 |
11 | 39108960753422 |
12 | 129999485aa21b |
13 | 5894b625720cc |
14 | 248a91c652819 |
15 | 1041b3b28730e |
hex | 7829a272eab7 |
132120214432439 has 2 divisors, whose sum is σ = 132120214432440. Its totient is φ = 132120214432438.
The previous prime is 132120214432433. The next prime is 132120214432487. The reversal of 132120214432439 is 934234412021231.
It is a weak prime.
It is an emirp because it is prime and its reverse (934234412021231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132120214432439 - 220 = 132120213383863 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132120214432396 and 132120214432405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132120214432433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060107216219 + 66060107216220.
It is an arithmetic number, because the mean of its divisors is an integer number (66060107216220).
Almost surely, 2132120214432439 is an apocalyptic number.
132120214432439 is a deficient number, since it is larger than the sum of its proper divisors (1).
132120214432439 is an equidigital number, since it uses as much as digits as its factorization.
132120214432439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 248832, while the sum is 41.
The spelling of 132120214432439 in words is "one hundred thirty-two trillion, one hundred twenty billion, two hundred fourteen million, four hundred thirty-two thousand, four hundred thirty-nine".
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