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132120243143402 = 266060121571701
BaseRepresentation
bin11110000010100110100100…
…001010010000001011101010
3122022210120102220112201021112
4132002212210022100023222
5114304124224221042102
61144555111330510322
736554241535106033
oct3602464412201352
9568716386481245
10132120243143402
1139108975983398
12129999561353a2
135894b684b5447
14248a9223a7a8a
151041b3da59252
hex7829a42902ea

132120243143402 has 4 divisors (see below), whose sum is σ = 198180364715106. Its totient is φ = 66060121571700.

The previous prime is 132120243143377. The next prime is 132120243143461. The reversal of 132120243143402 is 204341342021231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 77913969418321 + 54206273725081 = 8826889^2 + 7362491^2 .

It is a super-3 number, since 3×1321202431434023 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33030060785849 + ... + 33030060785852.

Almost surely, 2132120243143402 is an apocalyptic number.

132120243143402 is a deficient number, since it is larger than the sum of its proper divisors (66060121571704).

132120243143402 is an equidigital number, since it uses as much as digits as its factorization.

132120243143402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66060121571703.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 132120243143402 its reverse (204341342021231), we get a palindrome (336461585164633).

The spelling of 132120243143402 in words is "one hundred thirty-two trillion, one hundred twenty billion, two hundred forty-three million, one hundred forty-three thousand, four hundred two".

Divisors: 1 2 66060121571701 132120243143402