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132121020014381 is a prime number
BaseRepresentation
bin11110000010100111010010…
…011101110001111100101101
3122022210122110001100211220202
4132002213102131301330231
5114304132322110430011
61144555320401523245
736554300020312016
oct3602472235617455
9568718401324822
10132121020014381
1139109234457022
1212999b32343525
135894c6042a908
14248a99763200d
151041b86d6323b
hex7829d2771f2d

132121020014381 has 2 divisors, whose sum is σ = 132121020014382. Its totient is φ = 132121020014380.

The previous prime is 132121020014371. The next prime is 132121020014483. The reversal of 132121020014381 is 183410020121231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 122242985886025 + 9878034128356 = 11056355^2 + 3142934^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132121020014381 is a prime.

It is a super-2 number, since 2×1321210200143812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132121020014311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66060510007190 + 66060510007191.

It is an arithmetic number, because the mean of its divisors is an integer number (66060510007191).

Almost surely, 2132121020014381 is an apocalyptic number.

It is an amenable number.

132121020014381 is a deficient number, since it is larger than the sum of its proper divisors (1).

132121020014381 is an equidigital number, since it uses as much as digits as its factorization.

132121020014381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 29.

The spelling of 132121020014381 in words is "one hundred thirty-two trillion, one hundred twenty-one billion, twenty million, fourteen thousand, three hundred eighty-one".