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1321213020103 = 5147256695749
BaseRepresentation
bin10011001110011110011…
…011101100011111000111
311200022021121101112020101
4103032132123230133013
5133121321013120403
62450542404144531
7164311614242134
oct23163633543707
94608247345211
101321213020103
1146a361340169
12194087698147
1397788ba4942
1447d389cd58b
152457b3ee71d
hex1339e6ec7c7

1321213020103 has 4 divisors (see below), whose sum is σ = 1321469721000. Its totient is φ = 1320956319208.

The previous prime is 1321213020079. The next prime is 1321213020107. The reversal of 1321213020103 is 3010203121231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1321213020103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1321213020107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 128342728 + ... + 128353021.

It is an arithmetic number, because the mean of its divisors is an integer number (330367430250).

Almost surely, 21321213020103 is an apocalyptic number.

1321213020103 is a deficient number, since it is larger than the sum of its proper divisors (256700897).

1321213020103 is an equidigital number, since it uses as much as digits as its factorization.

1321213020103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 256700896.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1321213020103 its reverse (3010203121231), we get a palindrome (4331416141334).

The spelling of 1321213020103 in words is "one trillion, three hundred twenty-one billion, two hundred thirteen million, twenty thousand, one hundred three".

Divisors: 1 5147 256695749 1321213020103