Base | Representation |
---|---|
bin | 1100000001000011000100… |
… | …0000000101111110001101 |
3 | 1201210001211212011212002111 |
4 | 3000100301000011332031 |
5 | 3212431431211314131 |
6 | 44033323553224021 |
7 | 2532355116603331 |
oct | 300206100057615 |
9 | 51701755155074 |
10 | 13212141510541 |
11 | 4234268496526 |
12 | 1594727562011 |
13 | 74ab90557b4c |
14 | 33968483d7c1 |
15 | 17da289d0ab1 |
hex | c0431005f8d |
13212141510541 has 4 divisors (see below), whose sum is σ = 13212155697084. Its totient is φ = 13212127324000.
The previous prime is 13212141510511. The next prime is 13212141510569. The reversal of 13212141510541 is 14501514121231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 8684838470025 + 4527303040516 = 2947005^2 + 2127746^2 .
It is a cyclic number.
It is not a de Polignac number, because 13212141510541 - 27 = 13212141510413 is a prime.
It is a super-2 number, since 2×132121415105412 (a number of 27 digits) contains 22 as substring.
It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13212141510511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5590120 + ... + 7594321.
It is an arithmetic number, because the mean of its divisors is an integer number (3303038924271).
Almost surely, 213212141510541 is an apocalyptic number.
It is an amenable number.
13212141510541 is a deficient number, since it is larger than the sum of its proper divisors (14186543).
13212141510541 is a wasteful number, since it uses less digits than its factorization.
13212141510541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14186542.
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 13212141510541 its reverse (14501514121231), we get a palindrome (27713655631772).
The spelling of 13212141510541 in words is "thirteen trillion, two hundred twelve billion, one hundred forty-one million, five hundred ten thousand, five hundred forty-one".
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