Base | Representation |
---|---|
bin | 1100000001000011000100… |
… | …0110100111011100111101 |
3 | 1201210001211222101201202211 |
4 | 3000100301012213130331 |
5 | 3212431432131024131 |
6 | 44033324054020421 |
7 | 2532355140254626 |
oct | 300206106473475 |
9 | 51701758351684 |
10 | 13212143220541 |
11 | 4234269454251 |
12 | 1594728047711 |
13 | 74ab90a06295 |
14 | 339684b66a4d |
15 | 17da28c1c5b1 |
hex | c04311a773d |
13212143220541 has 2 divisors, whose sum is σ = 13212143220542. Its totient is φ = 13212143220540.
The previous prime is 13212143220533. The next prime is 13212143220569. The reversal of 13212143220541 is 14502234121231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13144359015225 + 67784205316 = 3625515^2 + 260354^2 .
It is a cyclic number.
It is not a de Polignac number, because 13212143220541 - 23 = 13212143220533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13212143220571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606071610270 + 6606071610271.
It is an arithmetic number, because the mean of its divisors is an integer number (6606071610271).
Almost surely, 213212143220541 is an apocalyptic number.
It is an amenable number.
13212143220541 is a deficient number, since it is larger than the sum of its proper divisors (1).
13212143220541 is an equidigital number, since it uses as much as digits as its factorization.
13212143220541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 13212143220541 its reverse (14502234121231), we get a palindrome (27714377341772).
The spelling of 13212143220541 in words is "thirteen trillion, two hundred twelve billion, one hundred forty-three million, two hundred twenty thousand, five hundred forty-one".
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