Search a number
-
+
13212143220541 is a prime number
BaseRepresentation
bin1100000001000011000100…
…0110100111011100111101
31201210001211222101201202211
43000100301012213130331
53212431432131024131
644033324054020421
72532355140254626
oct300206106473475
951701758351684
1013212143220541
114234269454251
121594728047711
1374ab90a06295
14339684b66a4d
1517da28c1c5b1
hexc04311a773d

13212143220541 has 2 divisors, whose sum is σ = 13212143220542. Its totient is φ = 13212143220540.

The previous prime is 13212143220533. The next prime is 13212143220569. The reversal of 13212143220541 is 14502234121231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13144359015225 + 67784205316 = 3625515^2 + 260354^2 .

It is a cyclic number.

It is not a de Polignac number, because 13212143220541 - 23 = 13212143220533 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13212143220571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606071610270 + 6606071610271.

It is an arithmetic number, because the mean of its divisors is an integer number (6606071610271).

Almost surely, 213212143220541 is an apocalyptic number.

It is an amenable number.

13212143220541 is a deficient number, since it is larger than the sum of its proper divisors (1).

13212143220541 is an equidigital number, since it uses as much as digits as its factorization.

13212143220541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 13212143220541 its reverse (14502234121231), we get a palindrome (27714377341772).

The spelling of 13212143220541 in words is "thirteen trillion, two hundred twelve billion, one hundred forty-three million, two hundred twenty thousand, five hundred forty-one".