Base | Representation |
---|---|
bin | 10011001110011111000… |
… | …010111010100000100101 |
3 | 11200022022022201212012011 |
4 | 103032133002322200211 |
5 | 133121331131114112 |
6 | 2450543412354221 |
7 | 164312100522064 |
oct | 23163702724045 |
9 | 4608268655164 |
10 | 1321223301157 |
11 | 46a367122501 |
12 | 19408b015971 |
13 | 9778b0643c6 |
14 | 47d3a1081db |
15 | 2457c280aa7 |
hex | 1339f0ba825 |
1321223301157 has 2 divisors, whose sum is σ = 1321223301158. Its totient is φ = 1321223301156.
The previous prime is 1321223301109. The next prime is 1321223301179. The reversal of 1321223301157 is 7511033221231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1253248904196 + 67974396961 = 1119486^2 + 260719^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1321223301157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1321223301457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660611650578 + 660611650579.
It is an arithmetic number, because the mean of its divisors is an integer number (660611650579).
Almost surely, 21321223301157 is an apocalyptic number.
It is an amenable number.
1321223301157 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321223301157 is an equidigital number, since it uses as much as digits as its factorization.
1321223301157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 1321223301157 its reverse (7511033221231), we get a palindrome (8832256522388).
The spelling of 1321223301157 in words is "one trillion, three hundred twenty-one billion, two hundred twenty-three million, three hundred one thousand, one hundred fifty-seven".
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