Base | Representation |
---|---|
bin | 11110000010101000101010… |
… | …101011110110110001010111 |
3 | 122022210210021012101221112111 |
4 | 132002220222223312301113 |
5 | 114304143340011133114 |
6 | 1145000123313131451 |
7 | 36554351501653003 |
oct | 3602505253666127 |
9 | 568723235357474 |
10 | 132122500099159 |
11 | 39109923974689 |
12 | 1299a285b59b87 |
13 | 5895137c6921b |
14 | 248aa9802d703 |
15 | 1041c21c76bc4 |
hex | 782a2aaf6c57 |
132122500099159 has 2 divisors, whose sum is σ = 132122500099160. Its totient is φ = 132122500099158.
The previous prime is 132122500099141. The next prime is 132122500099169. The reversal of 132122500099159 is 951990005221231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132122500099159 - 241 = 129923476843607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132122500099169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66061250049579 + 66061250049580.
It is an arithmetic number, because the mean of its divisors is an integer number (66061250049580).
Almost surely, 2132122500099159 is an apocalyptic number.
132122500099159 is a deficient number, since it is larger than the sum of its proper divisors (1).
132122500099159 is an equidigital number, since it uses as much as digits as its factorization.
132122500099159 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 437400, while the sum is 49.
The spelling of 132122500099159 in words is "one hundred thirty-two trillion, one hundred twenty-two billion, five hundred million, ninety-nine thousand, one hundred fifty-nine".
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