Base | Representation |
---|---|
bin | 11110000010101001001000… |
… | …110010000110110011001011 |
3 | 122022210211120101120022120101 |
4 | 132002221020302012303023 |
5 | 114304200403243213110 |
6 | 1145000245352110231 |
7 | 36554400143005003 |
oct | 3602511062066313 |
9 | 568724511508511 |
10 | 132123005054155 |
11 | 3910a062a05865 |
12 | 1299a3a7095377 |
13 | 58951b876776b |
14 | 248ab05115003 |
15 | 1041c5126d13a |
hex | 782a48c86ccb |
132123005054155 has 8 divisors (see below), whose sum is σ = 160086903211872. Its totient is φ = 104672205945408.
The previous prime is 132123005054077. The next prime is 132123005054177. The reversal of 132123005054155 is 551450500321231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132123005054155 - 217 = 132123004923083 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 128274761674 + ... + 128274762703.
It is an arithmetic number, because the mean of its divisors is an integer number (20010862901484).
Almost surely, 2132123005054155 is an apocalyptic number.
132123005054155 is a deficient number, since it is larger than the sum of its proper divisors (27963898157717).
132123005054155 is a wasteful number, since it uses less digits than its factorization.
132123005054155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 256549524485.
The product of its (nonzero) digits is 90000, while the sum is 37.
Adding to 132123005054155 its reverse (551450500321231), we get a palindrome (683573505375386).
The spelling of 132123005054155 in words is "one hundred thirty-two trillion, one hundred twenty-three billion, five million, fifty-four thousand, one hundred fifty-five".
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