Base | Representation |
---|---|
bin | 1100000001000011110001… |
… | …0010111100100111010011 |
3 | 1201210002100001202000221122 |
4 | 3000100330102330213103 |
5 | 3212432323214033243 |
6 | 44033354442512455 |
7 | 2532362610343445 |
oct | 300207422744723 |
9 | 51702301660848 |
10 | 13212331002323 |
11 | 4234355451502 |
12 | 159477ab0572b |
13 | 74abc08a316b |
14 | 3396a1a88495 |
15 | 17da3a461668 |
hex | c043c4bc9d3 |
13212331002323 has 2 divisors, whose sum is σ = 13212331002324. Its totient is φ = 13212331002322.
The previous prime is 13212331002317. The next prime is 13212331002329. The reversal of 13212331002323 is 32320013321231.
It is a balanced prime because it is at equal distance from previous prime (13212331002317) and next prime (13212331002329).
It is a cyclic number.
It is not a de Polignac number, because 13212331002323 - 210 = 13212331001299 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13212331002292 and 13212331002301.
It is not a weakly prime, because it can be changed into another prime (13212331002329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606165501161 + 6606165501162.
It is an arithmetic number, because the mean of its divisors is an integer number (6606165501162).
Almost surely, 213212331002323 is an apocalyptic number.
13212331002323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13212331002323 is an equidigital number, since it uses as much as digits as its factorization.
13212331002323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 13212331002323 its reverse (32320013321231), we get a palindrome (45532344323554).
The spelling of 13212331002323 in words is "thirteen trillion, two hundred twelve billion, three hundred thirty-one million, two thousand, three hundred twenty-three".
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