Base | Representation |
---|---|
bin | 11110000010101001100110… |
… | …011101101000011110100011 |
3 | 122022210212212002112202201202 |
4 | 132002221212131220132203 |
5 | 114304202413232103210 |
6 | 1145000411020551415 |
7 | 36554415400341350 |
oct | 3602514635503643 |
9 | 568725762482652 |
10 | 132123503003555 |
11 | 3910a298aa1598 |
12 | 1299a5059b256b |
13 | 589526798238b |
14 | 248ab512d5627 |
15 | 1041c7ed2d9a5 |
hex | 782a667687a3 |
132123503003555 has 16 divisors (see below), whose sum is σ = 191856649740480. Its totient is φ = 85269622106112.
The previous prime is 132123503003551. The next prime is 132123503003567. The reversal of 132123503003555 is 555300305321231.
It is a cyclic number.
It is not a de Polignac number, because 132123503003555 - 22 = 132123503003551 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132123503003551) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 111028153190 + ... + 111028154379.
It is an arithmetic number, because the mean of its divisors is an integer number (11991040608780).
Almost surely, 2132123503003555 is an apocalyptic number.
132123503003555 is a deficient number, since it is larger than the sum of its proper divisors (59733146736925).
132123503003555 is a wasteful number, since it uses less digits than its factorization.
132123503003555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 222056307598.
The product of its (nonzero) digits is 202500, while the sum is 38.
Adding to 132123503003555 its reverse (555300305321231), we get a palindrome (687423808324786).
The spelling of 132123503003555 in words is "one hundred thirty-two trillion, one hundred twenty-three billion, five hundred three million, three thousand, five hundred fifty-five".
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