Base | Representation |
---|---|
bin | 11110000010101010000101… |
… | …100001100101100111111110 |
3 | 122022210221012102010221111121 |
4 | 132002222011201211213332 |
5 | 114304210000134243032 |
6 | 1145000534434341154 |
7 | 36554434326023455 |
oct | 3602520541454776 |
9 | 568727172127447 |
10 | 132124024134142 |
11 | 3910a536180727 |
12 | 1299a63042a7ba |
13 | 589531b925381 |
14 | 248aba05cbb9c |
15 | 1041cb096ca97 |
hex | 782a858659fe |
132124024134142 has 8 divisors (see below), whose sum is σ = 200694720204000. Its totient is φ = 65225784066144.
The previous prime is 132124024134131. The next prime is 132124024134191. The reversal of 132124024134142 is 241431420421231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 132124024134098 and 132124024134107.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 418114000267 + ... + 418114000582.
It is an arithmetic number, because the mean of its divisors is an integer number (25086840025500).
Almost surely, 2132124024134142 is an apocalyptic number.
132124024134142 is a deficient number, since it is larger than the sum of its proper divisors (68570696069858).
132124024134142 is an equidigital number, since it uses as much as digits as its factorization.
132124024134142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 836228000930.
The product of its (nonzero) digits is 36864, while the sum is 34.
Adding to 132124024134142 its reverse (241431420421231), we get a palindrome (373555444555373).
The spelling of 132124024134142 in words is "one hundred thirty-two trillion, one hundred twenty-four billion, twenty-four million, one hundred thirty-four thousand, one hundred forty-two".
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