Base | Representation |
---|---|
bin | 10011001110100000000… |
… | …110110100111111010111 |
3 | 11200022100120020100120102 |
4 | 103032200012310333113 |
5 | 133121400210314333 |
6 | 2450545250124315 |
7 | 164312405041316 |
oct | 23164006647727 |
9 | 4608316210512 |
10 | 1321241104343 |
11 | 46a376182286 |
12 | 194094b8069b |
13 | 97791958934 |
14 | 47d3c62027d |
15 | 2457daeaae8 |
hex | 133a01b4fd7 |
1321241104343 has 2 divisors, whose sum is σ = 1321241104344. Its totient is φ = 1321241104342.
The previous prime is 1321241104331. The next prime is 1321241104399. The reversal of 1321241104343 is 3434011421231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1321241104343 - 236 = 1252521627607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1321241104543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660620552171 + 660620552172.
It is an arithmetic number, because the mean of its divisors is an integer number (660620552172).
Almost surely, 21321241104343 is an apocalyptic number.
1321241104343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321241104343 is an equidigital number, since it uses as much as digits as its factorization.
1321241104343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1321241104343 its reverse (3434011421231), we get a palindrome (4755252525574).
The spelling of 1321241104343 in words is "one trillion, three hundred twenty-one billion, two hundred forty-one million, one hundred four thousand, three hundred forty-three".
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