132124113333 has 24 divisors (see below), whose sum is σ = 199665805248. Its totient is φ = 87303230784.

The previous prime is 132124113293. The next prime is 132124113343. The reversal of 132124113333 is 333311421231.

132124113333 is a `hidden beast` number, since 1 + 3 + 212 + 4 + 113 + 333 = 666.

It is a de Polignac number, because none of the positive numbers 2^k-132124113333 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 132124113297 and 132124113306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132124113343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2378385 + ... + 2433302.

It is an arithmetic number, because the mean of its divisors is an integer number (8319408552).

Almost surely, 2^132124113333 is an apocalyptic number.

It is an amenable number.

132124113333 is a deficient number, since it is larger than the sum of its proper divisors (67541691915).

132124113333 is an equidigital number, since it uses as much as digits as its factorization.

132124113333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4811815 (or 4811803 counting only the distinct ones).

The product of its digits is 3888, while the sum is 27.

Adding to 132124113333 its reverse (333311421231), we get a palindrome (465435534564).

The spelling of 132124113333 in words is "one hundred thirty-two billion, one hundred twenty-four million, one hundred thirteen thousand, three hundred thirty-three".