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13212425533115 = 52642485106623
BaseRepresentation
bin1100000001000100000111…
…1011100011011010111011
31201210002120122121200211002
43000101001323203122323
53212433021414024430
644033412100555215
72532365136006434
oct300210173433273
951702518550732
1013212425533115
1142343a3847926
1215947a66b2b0b
1374ac07350443
143396b045448b
1517da438d5845
hexc0441ee36bb

13212425533115 has 4 divisors (see below), whose sum is σ = 15854910639744. Its totient is φ = 10569940426488.

The previous prime is 13212425533103. The next prime is 13212425533147. The reversal of 13212425533115 is 51133552421231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13212425533115 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1321242553307 + ... + 1321242553316.

It is an arithmetic number, because the mean of its divisors is an integer number (3963727659936).

Almost surely, 213212425533115 is an apocalyptic number.

13212425533115 is a deficient number, since it is larger than the sum of its proper divisors (2642485106629).

13212425533115 is an equidigital number, since it uses as much as digits as its factorization.

13212425533115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2642485106628.

The product of its digits is 108000, while the sum is 38.

Adding to 13212425533115 its reverse (51133552421231), we get a palindrome (64345977954346).

The spelling of 13212425533115 in words is "thirteen trillion, two hundred twelve billion, four hundred twenty-five million, five hundred thirty-three thousand, one hundred fifteen".

Divisors: 1 5 2642485106623 13212425533115