Base | Representation |
---|---|
bin | 11110000010101010010110… |
… | …001001110100000000111111 |
3 | 122022210221220212002121100011 |
4 | 132002222112021310000333 |
5 | 114304211033044124203 |
6 | 1145001022242044051 |
7 | 36554444254225633 |
oct | 3602522611640077 |
9 | 568727825077304 |
10 | 132124303114303 |
11 | 3910a6696a8645 |
12 | 1299a6a9949627 |
13 | 58953646737a6 |
14 | 248abc968cdc3 |
15 | 1041cca1c876d |
hex | 782a9627403f |
132124303114303 has 2 divisors, whose sum is σ = 132124303114304. Its totient is φ = 132124303114302.
The previous prime is 132124303114259. The next prime is 132124303114319. The reversal of 132124303114303 is 303411303421231.
It is a strong prime.
It is an emirp because it is prime and its reverse (303411303421231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132124303114303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132124303114343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66062151557151 + 66062151557152.
It is an arithmetic number, because the mean of its divisors is an integer number (66062151557152).
Almost surely, 2132124303114303 is an apocalyptic number.
132124303114303 is a deficient number, since it is larger than the sum of its proper divisors (1).
132124303114303 is an equidigital number, since it uses as much as digits as its factorization.
132124303114303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 132124303114303 its reverse (303411303421231), we get a palindrome (435535606535534).
The spelling of 132124303114303 in words is "one hundred thirty-two trillion, one hundred twenty-four billion, three hundred three million, one hundred fourteen thousand, three hundred three".
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