Base | Representation |
---|---|
bin | 10011001110100001000… |
… | …100111111101011111011 |
3 | 11200022101200220022111101 |
4 | 103032201010333223323 |
5 | 133121413343313313 |
6 | 2450551031312231 |
7 | 164312663414554 |
oct | 23164104775373 |
9 | 4608350808441 |
10 | 1321257401083 |
11 | 46a3843a3264 |
12 | 19409a51b677 |
13 | 97795143589 |
14 | 47d4086332b |
15 | 245802695dd |
hex | 133a113fafb |
1321257401083 has 2 divisors, whose sum is σ = 1321257401084. Its totient is φ = 1321257401082.
The previous prime is 1321257401033. The next prime is 1321257401207. The reversal of 1321257401083 is 3801047521231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1321257401083 - 237 = 1183818447611 is a prime.
It is a super-2 number, since 2×13212574010832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1321257401003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660628700541 + 660628700542.
It is an arithmetic number, because the mean of its divisors is an integer number (660628700542).
Almost surely, 21321257401083 is an apocalyptic number.
1321257401083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321257401083 is an equidigital number, since it uses as much as digits as its factorization.
1321257401083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 37.
The spelling of 1321257401083 in words is "one trillion, three hundred twenty-one billion, two hundred fifty-seven million, four hundred one thousand, eighty-three".
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