Base | Representation |
---|---|
bin | 10011001110100001000… |
… | …100111111101101110111 |
3 | 11200022101200220022122222 |
4 | 103032201010333231313 |
5 | 133121413343314312 |
6 | 2450551031312555 |
7 | 164312663415122 |
oct | 23164104775567 |
9 | 4608350808588 |
10 | 1321257401207 |
11 | 46a3843a3367 |
12 | 19409a51b75b |
13 | 97795143653 |
14 | 47d408633b9 |
15 | 24580269672 |
hex | 133a113fb77 |
1321257401207 has 2 divisors, whose sum is σ = 1321257401208. Its totient is φ = 1321257401206.
The previous prime is 1321257401083. The next prime is 1321257401227. The reversal of 1321257401207 is 7021047521231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1321257401207 - 230 = 1320183659383 is a prime.
It is a super-2 number, since 2×13212574012072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1321257401227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660628700603 + 660628700604.
It is an arithmetic number, because the mean of its divisors is an integer number (660628700604).
Almost surely, 21321257401207 is an apocalyptic number.
1321257401207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321257401207 is an equidigital number, since it uses as much as digits as its factorization.
1321257401207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23520, while the sum is 35.
The spelling of 1321257401207 in words is "one trillion, three hundred twenty-one billion, two hundred fifty-seven million, four hundred one thousand, two hundred seven".
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