Base | Representation |
---|---|
bin | 11110000010101111101100… |
… | …010111001110111011110111 |
3 | 122022211111201222102012000011 |
4 | 132002233230113032323313 |
5 | 114304304312334042221 |
6 | 1145003412054401051 |
7 | 36555036450544501 |
oct | 3602575427167367 |
9 | 568744658365004 |
10 | 132130044440311 |
11 | 39112045510875 |
12 | 1299b830660187 |
13 | 5895a6ac80a08 |
14 | 248b1b1da4d71 |
15 | 10420142671e1 |
hex | 782bec5ceef7 |
132130044440311 has 4 divisors (see below), whose sum is σ = 132134189988592. Its totient is φ = 132125898892032.
The previous prime is 132130044440257. The next prime is 132130044440347. The reversal of 132130044440311 is 113044440031231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132130044440311 - 27 = 132130044440183 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132130044440371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2072726331 + ... + 2072790076.
It is an arithmetic number, because the mean of its divisors is an integer number (33033547497148).
Almost surely, 2132130044440311 is an apocalyptic number.
132130044440311 is a deficient number, since it is larger than the sum of its proper divisors (4145548281).
132130044440311 is an equidigital number, since it uses as much as digits as its factorization.
132130044440311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4145548280.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 132130044440311 its reverse (113044440031231), we get a palindrome (245174484471542).
The spelling of 132130044440311 in words is "one hundred thirty-two trillion, one hundred thirty billion, forty-four million, four hundred forty thousand, three hundred eleven".
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