Base | Representation |
---|---|
bin | 10011001110100011110… |
… | …111101011001111101101 |
3 | 11200022111222001000222001 |
4 | 103032203313223033231 |
5 | 133122012341204013 |
6 | 2450555423252301 |
7 | 164314102511512 |
oct | 23164367531755 |
9 | 4608458030861 |
10 | 1321304241133 |
11 | 46a3a8885948 |
12 | 1940b214a091 |
13 | 977a1a63596 |
14 | 47d46b77309 |
15 | 2458441cddd |
hex | 133a3deb3ed |
1321304241133 has 2 divisors, whose sum is σ = 1321304241134. Its totient is φ = 1321304241132.
The previous prime is 1321304241107. The next prime is 1321304241137. The reversal of 1321304241133 is 3311424031231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 798267197764 + 523037043369 = 893458^2 + 723213^2 .
It is a cyclic number.
It is not a de Polignac number, because 1321304241133 - 29 = 1321304240621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1321304241137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660652120566 + 660652120567.
It is an arithmetic number, because the mean of its divisors is an integer number (660652120567).
Almost surely, 21321304241133 is an apocalyptic number.
It is an amenable number.
1321304241133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321304241133 is an equidigital number, since it uses as much as digits as its factorization.
1321304241133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 1321304241133 its reverse (3311424031231), we get a palindrome (4632728272364).
The spelling of 1321304241133 in words is "one trillion, three hundred twenty-one billion, three hundred four million, two hundred forty-one thousand, one hundred thirty-three".
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