Base | Representation |
---|---|
bin | 10011001110100011110… |
… | …111101101101111000111 |
3 | 11200022111222001112221220 |
4 | 103032203313231233013 |
5 | 133122012342020320 |
6 | 2450555423411423 |
7 | 164314102553325 |
oct | 23164367555707 |
9 | 4608458045856 |
10 | 1321304251335 |
11 | 46a3a8892582 |
12 | 1940b2153b73 |
13 | 977a1a68113 |
14 | 47d46b7ad15 |
15 | 24584420e40 |
hex | 133a3dedbc7 |
1321304251335 has 128 divisors (see below), whose sum is σ = 2256289136640. Its totient is φ = 659205388800.
The previous prime is 1321304251271. The next prime is 1321304251339. The reversal of 1321304251335 is 5331524031231.
It is not a de Polignac number, because 1321304251335 - 26 = 1321304251271 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1321304251296 and 1321304251305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1321304251339) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 898234650 + ... + 898236120.
It is an arithmetic number, because the mean of its divisors is an integer number (17627258880).
Almost surely, 21321304251335 is an apocalyptic number.
1321304251335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1321304251335 is a deficient number, since it is larger than the sum of its proper divisors (934984885305).
1321304251335 is a wasteful number, since it uses less digits than its factorization.
1321304251335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1989.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 1321304251335 its reverse (5331524031231), we get a palindrome (6652828282566).
The spelling of 1321304251335 in words is "one trillion, three hundred twenty-one billion, three hundred four million, two hundred fifty-one thousand, three hundred thirty-five".
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