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13213100232022 = 26606550116011
BaseRepresentation
bin1100000001000110101000…
…1001010100110101010110
31201210011022200011221201111
43000101222021110311112
53212440412124411042
644034003042045234
72532420640602565
oct300215211246526
951704280157644
1013213100232022
11423470a686129
12159495464981a
1374acb4071572
14339735cc3bdc
1517da82c5b517
hexc046a254d56

13213100232022 has 4 divisors (see below), whose sum is σ = 19819650348036. Its totient is φ = 6606550116010.

The previous prime is 13213100232001. The next prime is 13213100232029. The reversal of 13213100232022 is 22023200131231.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 13213100231984 and 13213100232002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13213100232029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3303275058004 + ... + 3303275058007.

It is an arithmetic number, because the mean of its divisors is an integer number (4954912587009).

Almost surely, 213213100232022 is an apocalyptic number.

13213100232022 is a deficient number, since it is larger than the sum of its proper divisors (6606550116014).

13213100232022 is an equidigital number, since it uses as much as digits as its factorization.

13213100232022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6606550116013.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 13213100232022 its reverse (22023200131231), we get a palindrome (35236300363253).

The spelling of 13213100232022 in words is "thirteen trillion, two hundred thirteen billion, one hundred million, two hundred thirty-two thousand, twenty-two".

Divisors: 1 2 6606550116011 13213100232022