Base | Representation |
---|---|
bin | 11110000010110000101100… |
… | …000000000111101011100011 |
3 | 122022211121111101110002110102 |
4 | 132002300230000013223203 |
5 | 114304314004200414412 |
6 | 1145004110034453015 |
7 | 36555105063651356 |
oct | 3602605400075343 |
9 | 568747441402412 |
10 | 132131112123107 |
11 | 39112543162749 |
12 | 1299ba8a13416b |
13 | 5895bab227a96 |
14 | 248b273ad029d |
15 | 1042077d678c2 |
hex | 782c2c007ae3 |
132131112123107 has 2 divisors, whose sum is σ = 132131112123108. Its totient is φ = 132131112123106.
The previous prime is 132131112123029. The next prime is 132131112123139. The reversal of 132131112123107 is 701321211131231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132131112123107 - 232 = 132126817155811 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132131112123107.
It is not a weakly prime, because it can be changed into another prime (132131112128107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66065556061553 + 66065556061554.
It is an arithmetic number, because the mean of its divisors is an integer number (66065556061554).
Almost surely, 2132131112123107 is an apocalyptic number.
132131112123107 is a deficient number, since it is larger than the sum of its proper divisors (1).
132131112123107 is an equidigital number, since it uses as much as digits as its factorization.
132131112123107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 29.
Adding to 132131112123107 its reverse (701321211131231), we get a palindrome (833452323254338).
The spelling of 132131112123107 in words is "one hundred thirty-two trillion, one hundred thirty-one billion, one hundred twelve million, one hundred twenty-three thousand, one hundred seven".
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