Base | Representation |
---|---|
bin | 1100000001000110101101… |
… | …0101000111101100101011 |
3 | 1201210011101001120102001121 |
4 | 3000101223111013230223 |
5 | 3212440432221214123 |
6 | 44034005032000111 |
7 | 2532421301515243 |
oct | 300215325075453 |
9 | 51704331512047 |
10 | 13213120101163 |
11 | 423471a917104 |
12 | 159495b230037 |
13 | 74acb820a258 |
14 | 3397387b6b23 |
15 | 17da8488375d |
hex | c046b547b2b |
13213120101163 has 2 divisors, whose sum is σ = 13213120101164. Its totient is φ = 13213120101162.
The previous prime is 13213120101161. The next prime is 13213120101179. The reversal of 13213120101163 is 36110102131231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13213120101163 - 21 = 13213120101161 is a prime.
Together with 13213120101161, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13213120101161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606560050581 + 6606560050582.
It is an arithmetic number, because the mean of its divisors is an integer number (6606560050582).
Almost surely, 213213120101163 is an apocalyptic number.
13213120101163 is a deficient number, since it is larger than the sum of its proper divisors (1).
13213120101163 is an equidigital number, since it uses as much as digits as its factorization.
13213120101163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 13213120101163 its reverse (36110102131231), we get a palindrome (49323222232394).
The spelling of 13213120101163 in words is "thirteen trillion, two hundred thirteen billion, one hundred twenty million, one hundred one thousand, one hundred sixty-three".
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