Base | Representation |
---|---|
bin | 1100000001000110110010… |
… | …0110011000001101001001 |
3 | 1201210011102112122121220211 |
4 | 3000101230212120031021 |
5 | 3212441003144334231 |
6 | 44034011112321121 |
7 | 2532421650544141 |
oct | 300215446301511 |
9 | 51704375577824 |
10 | 13213141402441 |
11 | 4234730946072 |
12 | 15949663a31a1 |
13 | 74acbc757a66 |
14 | 33973b55d921 |
15 | 17da8668eeb1 |
hex | c046c998349 |
13213141402441 has 2 divisors, whose sum is σ = 13213141402442. Its totient is φ = 13213141402440.
The previous prime is 13213141402427. The next prime is 13213141402463. The reversal of 13213141402441 is 14420414131231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9144448992441 + 4068692410000 = 3023979^2 + 2017100^2 .
It is a cyclic number.
It is not a de Polignac number, because 13213141402441 - 219 = 13213140878153 is a prime.
It is not a weakly prime, because it can be changed into another prime (13213141402421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606570701220 + 6606570701221.
It is an arithmetic number, because the mean of its divisors is an integer number (6606570701221).
Almost surely, 213213141402441 is an apocalyptic number.
It is an amenable number.
13213141402441 is a deficient number, since it is larger than the sum of its proper divisors (1).
13213141402441 is an equidigital number, since it uses as much as digits as its factorization.
13213141402441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 13213141402441 its reverse (14420414131231), we get a palindrome (27633555533672).
The spelling of 13213141402441 in words is "thirteen trillion, two hundred thirteen billion, one hundred forty-one million, four hundred two thousand, four hundred forty-one".
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