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132132012005647 is a prime number
BaseRepresentation
bin11110000010110001100001…
…101000111001100100001111
3122022211200211002201212020101
4132002301201220321210033
5114304322330033140042
61145004335222231531
736555136301560543
oct3602614150714417
9568750732655211
10132132012005647
1139112965114825
12129a009b5855a7
135895cc27acb64
14248b31b419a23
1510420cbd6e6b7
hex782c61a3990f

132132012005647 has 2 divisors, whose sum is σ = 132132012005648. Its totient is φ = 132132012005646.

The previous prime is 132132012005611. The next prime is 132132012005663. The reversal of 132132012005647 is 746500210231231.

It is a strong prime.

It is an emirp because it is prime and its reverse (746500210231231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132132012005647 - 215 = 132132011972879 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132132012005947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66066006002823 + 66066006002824.

It is an arithmetic number, because the mean of its divisors is an integer number (66066006002824).

Almost surely, 2132132012005647 is an apocalyptic number.

132132012005647 is a deficient number, since it is larger than the sum of its proper divisors (1).

132132012005647 is an equidigital number, since it uses as much as digits as its factorization.

132132012005647 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 37.

Adding to 132132012005647 its reverse (746500210231231), we get a palindrome (878632222236878).

The spelling of 132132012005647 in words is "one hundred thirty-two trillion, one hundred thirty-two billion, twelve million, five thousand, six hundred forty-seven".