Base | Representation |
---|---|
bin | 1100000001000111000000… |
… | …1010111000001011100001 |
3 | 1201210011120201100211222221 |
4 | 3000101300022320023201 |
5 | 3212441114013132431 |
6 | 44034021052231041 |
7 | 2532423305643133 |
oct | 300216012701341 |
9 | 51704521324887 |
10 | 13213201302241 |
11 | 4234761738736 |
12 | 159498246b481 |
13 | 74accbc9b225 |
14 | 3397454b3053 |
15 | 17da8ba73111 |
hex | c04702b82e1 |
13213201302241 has 2 divisors, whose sum is σ = 13213201302242. Its totient is φ = 13213201302240.
The previous prime is 13213201302239. The next prime is 13213201302251. The reversal of 13213201302241 is 14220310231231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12605730707025 + 607470595216 = 3550455^2 + 779404^2 .
It is a cyclic number.
It is not a de Polignac number, because 13213201302241 - 21 = 13213201302239 is a prime.
Together with 13213201302239, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13213201302251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606600651120 + 6606600651121.
It is an arithmetic number, because the mean of its divisors is an integer number (6606600651121).
Almost surely, 213213201302241 is an apocalyptic number.
It is an amenable number.
13213201302241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13213201302241 is an equidigital number, since it uses as much as digits as its factorization.
13213201302241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13213201302241 its reverse (14220310231231), we get a palindrome (27433511533472).
The spelling of 13213201302241 in words is "thirteen trillion, two hundred thirteen billion, two hundred one million, three hundred two thousand, two hundred forty-one".
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