Base | Representation |
---|---|
bin | 11110000010110001100111… |
… | …100010111011000111010110 |
3 | 122022211201002000012111110022 |
4 | 132002301213202323013112 |
5 | 114304323030420234142 |
6 | 1145004353122225142 |
7 | 36555141614101454 |
oct | 3602614742730726 |
9 | 568751060174408 |
10 | 132132111102422 |
11 | 39112a06049692 |
12 | 129a01087b51b2 |
13 | 589600a1984c2 |
14 | 248b32a6539d4 |
15 | 10420d58e66d2 |
hex | 782c678bb1d6 |
132132111102422 has 4 divisors (see below), whose sum is σ = 198198166653636. Its totient is φ = 66066055551210.
The previous prime is 132132111102367. The next prime is 132132111102469. The reversal of 132132111102422 is 224201111231231.
132132111102422 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 132132111102391 and 132132111102400.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33033027775604 + ... + 33033027775607.
It is an arithmetic number, because the mean of its divisors is an integer number (49549541663409).
Almost surely, 2132132111102422 is an apocalyptic number.
132132111102422 is a deficient number, since it is larger than the sum of its proper divisors (66066055551214).
132132111102422 is an equidigital number, since it uses as much as digits as its factorization.
132132111102422 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66066055551213.
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 132132111102422 its reverse (224201111231231), we get a palindrome (356333222333653).
The spelling of 132132111102422 in words is "one hundred thirty-two trillion, one hundred thirty-two billion, one hundred eleven million, one hundred two thousand, four hundred twenty-two".
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