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132133000320031 is a prime number
BaseRepresentation
bin11110000010110010011100…
…100011000001010000011111
3122022211210100222102102200211
4132002302130203001100133
5114304331341040220111
61145005021245233251
736555202632241564
oct3602623443012037
9568753328372624
10132133000320031
1139113321a86a77
12129a0316562827
13589611c488179
14248b3b27a486b
1510421389e3521
hex782c9c8c141f

132133000320031 has 2 divisors, whose sum is σ = 132133000320032. Its totient is φ = 132133000320030.

The previous prime is 132133000319981. The next prime is 132133000320077. The reversal of 132133000320031 is 130023000331231.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132133000320031 is a prime.

It is a super-2 number, since 2×1321330003200312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132133000319984 and 132133000320011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132133000323031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66066500160015 + 66066500160016.

It is an arithmetic number, because the mean of its divisors is an integer number (66066500160016).

Almost surely, 2132133000320031 is an apocalyptic number.

132133000320031 is a deficient number, since it is larger than the sum of its proper divisors (1).

132133000320031 is an equidigital number, since it uses as much as digits as its factorization.

132133000320031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 132133000320031 its reverse (130023000331231), we get a palindrome (262156000651262).

The spelling of 132133000320031 in words is "one hundred thirty-two trillion, one hundred thirty-three billion, three hundred twenty thousand, thirty-one".