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1321331342143 = 5922395446477
BaseRepresentation
bin10011001110100101011…
…111000011101100111111
311200022120212000220120011
4103032211133003230333
5133122041310422033
62451002232204051
7164314552044301
oct23164537035477
94608525026504
101321331342143
1146a41210627a
121940bb239627
13977a7561b97
1447d4a5cd971
15245869c2ccd
hex133a57c3b3f

1321331342143 has 4 divisors (see below), whose sum is σ = 1343726788680. Its totient is φ = 1298935895608.

The previous prime is 1321331342129. The next prime is 1321331342161. The reversal of 1321331342143 is 3412431331231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1321331342143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1321331342113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11197723180 + ... + 11197723297.

It is an arithmetic number, because the mean of its divisors is an integer number (335931697170).

Almost surely, 21321331342143 is an apocalyptic number.

1321331342143 is a deficient number, since it is larger than the sum of its proper divisors (22395446537).

1321331342143 is an equidigital number, since it uses as much as digits as its factorization.

1321331342143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22395446536.

The product of its digits is 15552, while the sum is 31.

Adding to 1321331342143 its reverse (3412431331231), we get a palindrome (4733762673374).

The spelling of 1321331342143 in words is "one trillion, three hundred twenty-one billion, three hundred thirty-one million, three hundred forty-two thousand, one hundred forty-three".

Divisors: 1 59 22395446477 1321331342143