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13213451130577 is a prime number
BaseRepresentation
bin1100000001000111111100…
…0011111001011011010001
31201210012020010110110001021
43000101333003321123101
53212442121442134302
644034101535035441
72532432431311465
oct300217703713321
951705203413037
1013213451130577
11423487a764435
121594a3206bb81
1374b03b980749
1433976a7464a5
1517daa3971437
hexc047f0f96d1

13213451130577 has 2 divisors, whose sum is σ = 13213451130578. Its totient is φ = 13213451130576.

The previous prime is 13213451130541. The next prime is 13213451130613. The reversal of 13213451130577 is 77503115431231.

13213451130577 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (13213451130541) and next prime (13213451130613).

It can be written as a sum of positive squares in only one way, i.e., 13097153762001 + 116297368576 = 3618999^2 + 341024^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13213451130577 is a prime.

It is not a weakly prime, because it can be changed into another prime (13213451130527) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6606725565288 + 6606725565289.

It is an arithmetic number, because the mean of its divisors is an integer number (6606725565289).

Almost surely, 213213451130577 is an apocalyptic number.

It is an amenable number.

13213451130577 is a deficient number, since it is larger than the sum of its proper divisors (1).

13213451130577 is an equidigital number, since it uses as much as digits as its factorization.

13213451130577 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 264600, while the sum is 43.

The spelling of 13213451130577 in words is "thirteen trillion, two hundred thirteen billion, four hundred fifty-one million, one hundred thirty thousand, five hundred seventy-seven".