Base | Representation |
---|---|
bin | 100111011000010… |
… | …1111111100100111 |
3 | 10102002110011222102 |
4 | 1032300233330213 |
5 | 10201234332101 |
6 | 335042122315 |
7 | 44513506256 |
oct | 11660577447 |
9 | 3362404872 |
10 | 1321402151 |
11 | 618995aa3 |
12 | 30a65039b |
13 | 1809bc684 |
14 | c76d279d |
15 | 7b01b86b |
hex | 4ec2ff27 |
1321402151 has 2 divisors, whose sum is σ = 1321402152. Its totient is φ = 1321402150.
The previous prime is 1321402123. The next prime is 1321402189. The reversal of 1321402151 is 1512041231.
It is a weak prime.
It is an emirp because it is prime and its reverse (1512041231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1321402151 - 222 = 1317207847 is a prime.
It is a super-2 number, since 2×13214021512 = 3492207289334853602, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1321402051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660701075 + 660701076.
It is an arithmetic number, because the mean of its divisors is an integer number (660701076).
Almost surely, 21321402151 is an apocalyptic number.
1321402151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321402151 is an equidigital number, since it uses as much as digits as its factorization.
1321402151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 20.
The square root of 1321402151 is about 36351.0955955938. The cubic root of 1321402151 is about 1097.3495834940.
Adding to 1321402151 its reverse (1512041231), we get a palindrome (2833443382).
The spelling of 1321402151 in words is "one billion, three hundred twenty-one million, four hundred two thousand, one hundred fifty-one".
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